what is force of gravity experienced by an object of mass 2 kg placed on the surface of the earth given that mass of Earth is equal to 6 into 10 to the power 24 kg radius of the earth 6.4 into 10 to the power 6 metre and gravity is equal to 6.7 into 10 to the power minus 11
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Answer:
Object mass = 2kg
Mass of Earth = 6*10^24 kg
Radius of Earth = 6.4*10^6 m
Gravitational Constant (G) = 6.7*10^-11 Nm^2/kg^2
F = (Gm1m2)/r^2
= (6.7*2*6)*(10^24-11) / (6.4)^2 . (10^6)^2
= 80.4*10^13 / 40.96*10^12 N
= (80.4/40.96) . (10^13-12) N
= 1.96*10 N
= 19.6 N
Hope this helps.
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