Physics, asked by pawaryashvardhan, 5 months ago

What is free fall? Write the equations of motion for a body falling freely downwards.

Answers

Answered by Anonymous
4

Answer:

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.

Thus acceleration of freely falling body  a=g=9.8 m/s2  (Taking downward direction to be positive)

Initial speed of that body  u=0

Equations of motion :

(i) :  v=gt

(ii) :  S=21gt2

(iii) : v2=2gS

hope this much helps uh ❣

Answered by Laiba12210
1

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s 2

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s 2 (Taking downward direction to be positive)

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s 2 (Taking downward direction to be positive)Initial speed of that body u=0

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s 2 (Taking downward direction to be positive)Initial speed of that body u=0Equations of motion :

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s 2 (Taking downward direction to be positive)Initial speed of that body u=0Equations of motion :(i) : v=gt

A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.Thus acceleration of freely falling body a=g=9.8 m/s 2 (Taking downward direction to be positive)Initial speed of that body u=0Equations of motion :(i) : v=gt(ii) : S= 1/2 gt^2

2 (iii) : v2 =2gS

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