Question

What is [HCl] if a 25⋅mL volume of [NaOH] of 0.250⋅mol⋅L−1 concentration reaches an endpoint with a 22.5⋅mL volume of the acid?

Answer 1

Hi there,,

◇ In neutralizatio reaction the number of moles for hydroxide anion equals number of hydronium cation ,, so we can write the relation as the following equation

◇ NaOH + HCL=> NaCl + H2O

C×V÷ a for acid = C×V ÷ b for base

C× 25 = 0.25 × 22.5

So [ HCL] = 0.25×22.5÷25 =

0.225 mol / l

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