Math, asked by srinathgadipelp77ry7, 1 year ago

what is integral of sin^(-1)

Answers

Answered by AJAYMAHICH
1
Let I=∫sin−1xdxI=∫sin−1xdx

=∫1⋅sin−1xdx=∫1⋅sin−1xdx

by using integration by parts

I=sin−1x∫1dx−∫I=sin−1x∫1dx−∫(ddxsin−1x∫1dx)dx(ddxsin−1x∫1dx)dx

=xsin−1x−∫(x1−x2−−−−−√)dx=xsin−1x−∫(x1−x2)dx

=xsin−1x+∫−2x21−x2−−−−−√=xsin−1x+∫−2x21−x2

Put 1−x2=t1−x2=t

⟹−2xdx=dt⟹−2xdx=dt

∴I=xsin−1x+∫12t√∴I=xsin−1x+∫12t

=xsin−1x+t√+c=xsin−1x+t+c

⟹I=xsin−1x+1−x2−−−−−√+c⟹I=xsin−1x+1−x2+c


Answered by Vikashkherwal
0
d( costhete) it will help you for the solution
Answered by Vikashkherwal
0
d( costhete) it will help you for the solution
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