Question

What is ionisation constant of hocl if kb of ocl- is 4×10^-10?

Answer 1

Hypochlorous acid(HOCl)  is a weak acid.The equation representing the ionisation of hypochlorous acid :

$HOCl(aq)+H_{2}O(l)---->OCl^{-} (aq)+H_{3} O^{+}$

The acid dissociation constant or ionisation constant of Hypochlorous acid can be represented as :

$K_{a}  =\frac{prdoucts}{reactants}$

                =$\frac{[OCl^{-}][H_{3} O^{+}]  }{[HOCl]}$

The conjugate base of HOCl is $OCl^{-}$. The base dissociation constant $K_{b}$ of $OCl^{-}$ can be calculated from $K_{a} and [tex] K_{W}$, ionic product of water by using the formula

$K_{a}*K_{b} =K_{W}$

$K_{a} =\frac{1.0*10^{-14} }{4*10^{-10} }$

$2.5*10^{-5}$

Therefore the ionisation constant  of HOCl $2.5*10^{-5}$

Answer 2

above answer is correct ...
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