Question

what is loga-logb?????​

Answer 1

Answer:

Let logA= m then e^m=A……………(1)

and logb=n then e^n. =B……………….(2)

Multiplying eqn. (1)and (2)

e^m×e^n=A×B

or. e^(m+n)= A.B

or. m+n= log. A.B

Putting m=log A and n=logB

logA+logB=log A.B. Answer

Dividing eqn (1)by (2)

e^m/e^n= A/B

or. e^(m-n) =A/B

or. m-n = log A/B

Putting m=logA. and n = logB

or. logA -logB. = log A/B. Answer.

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Answer 2

Answer:

log a +logb=logab

loga -logb=loga/b

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