Physics, asked by mudavathbharathi1, 9 months ago

what is malus law and it's formula

Answers

Answered by hemanth101
1

Answer:

Malus law formula

The light intensity, which passes through the ideal polarizer can be calculated as: intensity = initial_intensity * cos²θ , ... initial_intensity is the irradiance of incident light, θ is the angle between the light polarization and the axis of the polarizer, intensity is the output irradiance.

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Answered by ferdin
0

Answer:

Malus law states that the intensity of polarised light(wave) after passing through analysers is squre of cosine of angle between polariser and analyser multiply by the original intensity.

Malus' law: I1 = Io cos2(q) where q is the angle between the polarization direction of the light and the transmission axis of the polarizer. Unpolarized light with an intensity of Io = 16 W/m2 is incident on a pair of polarizers. The first polarizer has its transmission axis aligned at 50o from the vertical.

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