What is maolarity of the solution which contain 32.0g of methly alcohol (CH3OH) in 200 ml solution
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Answer:
5M
Explanation:
moles=n= 32/32(molar mass of ch3oh) =1
molarity=no of moles of solute/litre of solution
molarity=1/200(ml) *1000
=5M(molar)
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