Question

what is mass of methanol is required to be dissolved in 8g of water to produce 2.00m solution?​

Answer 1

Molarity (M) = w²/M² x (1000/V) where

M= Molarity = 0.2

w²= weight of solute= ?

M² = Mol.Wt of solute = 121

V= Vo.of solution in ml= 250.

So w²= M x M²/ 1000 x V

=0.25 x121 x 250/1000= 121/16

= 7.5625.

So if you dissolve 7.5625- g of CaCl2 in water, dissolve well and then add distilled in a 250- ml standard flask upto the mark and shake well for uniform Concentration, you will get 0.25- M CaCl2– solution.

Answer 2

Answer:

Molarity (M) = w²/M² x (1000/V) where

M= Molarity = 0.2

w²= weight of solute= ?

M² = Mol.Wt of solute = 121

V= Vo.of solution in ml= 250.

So w²= M x M²/ 1000 x V

=0.25 x121 x 250/1000= 121/16

= 7.5625.

So if you dissolve 7.5625- g of CaCl2 in water, dissolve well and then add distilled in a 250- ml standard flask upto the mark and shake well for uniform Concentration, you will get 0.25- M CaCl2– solution.

Explanation: