Question

What is mass of sulphuric acid required to neutralize 280 ml of 4.5 molar pure diverter?

Answer 1

equivalent mass of H2SO4=98/2 gm

=49 gm

V=280 ml

Molarity=4.5 M

let the mass required be x

then

no of gram equivalents of H2SO4=no of gram equivalents of the base

x/49=280/1000*4.5

x=61.74 gm

Hope this helps

(i have assumed the base to be monoacidic as acidity isn't given)