Question

What is mean by uniform motion?
A particle starts from rest with constant acceleration of 10m/s square find final velocity 10sec ?, Distance covered after 10sec?, Distance covered in 3rd second ?, Find time when velocity becomes 50m/s ?, Distance covered when velocity becomes 50m/s ?

Answer 1

Answer: Uniform motion is motion wherein the particle/object in motion covers equal distances in equals intervals of time consistently/ the velocity of the particle remains constant/there is no acceleration.

The final velocity is 100m/s after 10s.

The distance covered in the third second is 45m.

It takes 5s to reach a velocity of 50m/s.

It covers 125m when it reaches this velocity.

Explanation: So, initial velocity (u) = 0m/s as it is in rest.

Final velocity (v) = ?

Acceleration (a) = 10m/s^2

t = 10s

As v - u/t = a, v/10 = 10 or v = 100m/s. (Ans.)

For distance (s), we use the formula s = ut + at^2/2

or s = 10x3x3/2 or s = 45m. (Ans.)

For time, we again use v - u/t = a

or 50/t = 10 >>> t = 5. (Ans.)

For distance (ii), we use v^2 - u^2 = 2as

or 2,500 = 20s

=) s = 125m. (Ans.)