what is molar concentration of solution containing 10g/L of k2Cr2O7
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Answer:
Explanation:
The reactions involved may be given as:
Cr
2
O
7
2−
+6I
−
+14H
+
→2Cr
3+
+3I
2
+7H
2
O
3[I
2
+2Na
2
S
2
O
3
]→3[2NaI+Na
2
S
4
O
6
]
1 mole K
2
Cr
2
O
7
≡6 moles of Na
2
S
2
O
3
....(i)
No. of moles of hypo =
M.w.(158)
Mass
=
1000×158
E×N×V
=
1000×158
158×1/20×15
=7.5×10
−4
mole
No. of moles of K
2
Cr
2
O
7
=
6
1
[No. of moles of Na
2
S
2
O
3
]
=1.25×10
−4
mole
Mass of K
2
Cr
2
O
7
in 10 mL solution =1.25×10
−4
×294
=0.03675 g
Weight of K
2
Cr
2
O
7
in 10 mL solution =3.675 g/L
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