What is molarity????
Answers
Answered by
18
Hey there!
Answer!
: Molarity of a solution is defined as the number of moles of the solute dissolved per litre of the solution. I is represented as . Thus a solution, which contains one gram mole of the the solution dissolved per litre* of the solution is regarded as .
M =
Let this is the (1) equation.
:
1) Calculate the Molarity of Pure water.
Solution: Density of water = 1gm/L
Mass of 1000mL of water = Volume × Density
= 1000 × 1 = 1000g.
Moles of water = 1000/18 = 55.55 mol.
Now Using the equation ( 1 ) and 55.55 mol of H2o are present in 1000mL or 1L of water :
= Molarity =
Molarity is one of the common measures of expressing concentration which is frequently used in laboratory.
#Be Brainly.
Answer!
: Molarity of a solution is defined as the number of moles of the solute dissolved per litre of the solution. I is represented as . Thus a solution, which contains one gram mole of the the solution dissolved per litre* of the solution is regarded as .
M =
Let this is the (1) equation.
:
1) Calculate the Molarity of Pure water.
Solution: Density of water = 1gm/L
Mass of 1000mL of water = Volume × Density
= 1000 × 1 = 1000g.
Moles of water = 1000/18 = 55.55 mol.
Now Using the equation ( 1 ) and 55.55 mol of H2o are present in 1000mL or 1L of water :
= Molarity =
Molarity is one of the common measures of expressing concentration which is frequently used in laboratory.
#Be Brainly.
Answered by
15
Hey !!
MOLARITY
It is defined as number of moles of solute dissolved in one litre of solution.
Molarity = Moles of solute / Volume of solution (in litre)
Units of molarity is mol L⁻¹ or M (molar). Molarity changes with change in temperature as volume changes with change in temperature.
EXAMPLE
Question = A solution of glucose ( molar mass = 180 g mol⁻¹) in water is labelled as 10% (by mass). What would be the molarity of the solution ?
( DENSITY OF SOLUTION = 1.2 g mL⁻¹ )
Solution
Let the mass of solution = 100 g
Now, Mass of glucose = 10 g
Number of moles of glucose = Mass of glucose / Molar mass
= 10 g / 180 g mol⁻¹ = 0.056 mol
Volume of the solution = Mass of solution / Density of solution
= 100 g / 1.2 g mL⁻¹
= 83.3 mL
= 83.3 / 1000 L
= 0.083 L
Molarity = Moles of solute / Volume of solution in litre
= 0.056 mol / 0.09 kg
= 0.62 mol kg⁻¹
FINAL RESULT ---> 0.62 mol kg⁻¹
Similar questions