what is molarity of glucose (c6h12o6) if its 18 g is dissolved in enough water to make a final volume of 2 l
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molarity = no. of moles of solute / volume of solution in litres
= weight /molecular mass / volume of solution in litres
= 180/18 /2 = 10/2 = 5M
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= weight /molecular mass / volume of solution in litres
= 180/18 /2 = 10/2 = 5M
here is your answer...
if you are happy with my answer please mark me....
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