what is the least number that should be multiplied to 100! to make it perfectly divisible by 350? a. 2 b. 3 c. 6 d. 9 e. 27
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(c.)6 is the answer which u required
Hope it's helpful
Hope it's helpful
Answered by
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Step-by-step explanation:
Given what is the least number that should be multiplied to 100! to make it perfectly divisible by 3^50?
- So 100! is 100 x 99 x 98 x 97……….and so on up to 1
- Now the numbers from 1to100 divisible by 3 is 33 (3,6,9……99) ( l = (a + (n – 1)d)
- So to make it perfectly divisible we have 3^50 – 33 = 3^17
- Since 9 has two 3’s, multiples of 9 in 100 will be 11
- Also 27 has three 3’s multiples of 27 in 100 will be 3
- Again 81 has four 3’s multiples of 81 in 100 will be 1
- So the total number of 3,9,27,81 in 100 will be 33 + 11 + 3 + 1 = 48
- So we get 3^50 – 48
- 3^2
- 9
- Therefore the least number that should be multiplied to 100! to make it perfectly divisible by 3^50 is 9
Reference link will be
https://brainly.in/question/22305709
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