What is normality of solution, when 1000
ml 0.25N NaoH mixed with 50 ml of 0.1N NaoH
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Explanation:
Resultant Normality = (V1N1 + V2N2) ÷ (V1+V2)
= (1000*0.25 + 50*0.1) ÷ (1000+50)
= (250+5) ÷ 1050 = 255 ÷ 1050 = 0.24N
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