Question

what is observed when 2 ml of dilute hydrochloric acid is added to one gram of sodium carbonate taken in a clean and dry test tube write chemical equation for the reaction involved

Answer 1

Answer:

2HCl + Na2CO3= 2NaCl + H2O + CO2

this is neutralization reaction

strong acid reacts with strong base to form a neutral salt.

also, carbon dioxide is liberated.

can be written as-

2HCl + Na2CO3 = 2NaCl + H2CO3

Dilute Hydrochloric Acid + Sodium carbonate→→Sodium chloride +Carbon Di Oxide + Water

So in an Equation form-

2HCL(dil) + Na₂Co₃ →→2NaCl + Co₂ + H₂O

Since any Metal Carbonate reacts with any of the acid . It produce Salt, Water as well as Carbon Di-oxide . 

So the above resulting reaction further produce Sodium chloride water carbon di-oxide .

So as per reaction, The characteristics are -

1- A Normal Salt of Sodium & Chlorine is produced. 

2- During the reaction The Carbon Di-oxide is evolved with a brisk effervescence & when a moist blue litmus is brought near it, The litmus turns Faint Red .

3- During the reaction, A stable liquid which usually doesn't have any Affect on Litmus paper (Water) is produced. 

Answer 2

Answer:

I hope u understand .....