Physics, asked by sujitsingh2866, 1 year ago

What is observed when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube? (ii) what type if reaction is this? (iii) write a balanced chemical equation to represent the above reaction?

Answers

Answered by Anonymous
1126

Hi there !!

Lead nitrate = Pb[NO]₂
Potassium Iodide = KI

When Lead Nitrate and Potassium Iodide are mixed we get Potassium Nitrate and an insoluble solid [ precipitate ] lead iodide.



Colour of the precipitate formed is Yellow [ Lead Iodide ]


KI + Pb[NO₃]₂ -----> KNO₃ + PbI₂
-----> UNBALANCED EQUATION

2Kl+ Pb[NO₃]₂ -----> 2KNO₃ + PbI₂
----> BALANCED EQUATION

This is an example of double displacement reaction.

Also , as yellow precipitate is formed , this is also an example of precipitation reaction
Answered by koksant
132
double displacement reaction will occur

for equation refer the attachment
Attachments:
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