what is observed when a solution of potassium iodine is added to a solution of lead nitrate taken in a test tube? what type of reaction is this? what is the colour of the product formed? write a balanced chemical equation to represent the above reaction?
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When potassium iodide solution is added to lead nitrate solution, then a yellow percipitate of lead iodide is produced along with potassium nitrate solution. This is a double displacement reaction. The equation of this reaction is :
Pb(NO3)2 (aq) + 2KI (aq) ====> PbI2 (s) + 2KNO3 (aq)
Pb(NO3)2 (aq) + 2KI (aq) ====> PbI2 (s) + 2KNO3 (aq)
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when a solution of potassium iodide is added to lead nitrate ,,,,, lead iodide and potassium nitrate are formed.....a ppt of lead iodide is formed which is yellow in colour ........this is a precipitation and double displacement reaction......
2KI + Pb(NO3)2 ----> 2KNO3 + PbI2
hope it will help uh
2KI + Pb(NO3)2 ----> 2KNO3 + PbI2
hope it will help uh
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