What is "%" Operator inc
Operator in c language? what
will be the result for 15% 15 in c
longuay
programing language
Answers
Answered by
0
Explanation:
int main()
{
float a ;
int b ;
a = 2.0 ;
b = 9 ;
printf ( "Value of b/a is : %f\n" , b/a ) ;
return 0;
}
Answered by
1
Question:-
What is "%" Operator in C Language?
What will be the result for 15 % 15 in C programming language.
Answer:
% is a Arithmetic Operator in C Language.
% returns the remainder after the division.
Result of 15 % 15 is 0.
Lets implement 15 % 15 in the program.
#include<stdio.h>
int main(){
int a= 15, b= 15;
printf("The value of a % b is %d \n", a % b);
return 0;
}
OUTPUT
The value of a % b is 0.
Note: Program has been run in the above attachment with output attached.
Attachments:
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