Question

what is orbital angular momentum of p-electron ​

Answer 1

Explanation:

orbital angular momentum= √l(l+1) h/2π

here, l of p electron is 1

1. by substituting values we get p OAM=1

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Answer 2

Orbital angular momentum of an electron in particular orbital is given by under root l(l+1) h/2pi where `l` is azimuthal quantum no. For p orbital l=1 so orbital angular momentum is \/2 h/2pi. h/2pi comes from the wave nature consideration of electron. Waves associated with electrons so circumference of a circle must be integral multiple of wavelength. So only these orbits are permissible otherwise wave will intersect and amplitude become zero that means no possibility of electron to be found in that orbit.

The formulae for finding out the orbital angular momentum is under roor l(l+1) × h/2pi , as we know that lfor p subshell =1 therefore keeping the values we get = under root 1(1+1)×h/2pi =underroot 2 × h/2pi or h/under root 2×pi.

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