Question

what is oxidation number of Boron in boric acid{H3BO3)​

Answer 1

Answer:

here is ur ans mate

Explanation:

The molecular formula for Boric acid is H3BO3.

Net oxidation state of H in H3BO3 = (3 × 1) = 3

Net oxidation state of O in H3BO3 = (3 × -2) =-6

Let, oxidation state of B in H3BO3 = x

For neutrality of the compound, sum of oxidation states (of each element in the compound) is zero.

3 — 6 + x = 0

-3 + x = 0

x = +3

Answer 2

Answer:

3+x+(-6)=0

Explanation:

Therefore ans is 3