What is oxidation number of N in Cu(NO3)2 ?
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Answer: N=+3
Explanation:
Cu(NO3)2=0
let the oxidation no. of N be x
⇒+2(x+(-2)3)2=0
⇒+2(2x-6)2=0
⇒+2(4x-12)=0
⇒+8x-24=0
⇒+8x=+24
⇒x=24/8
⇒x=+3
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The first step is jot down the charges of the elements since it is an ionic bond. Cu=+2, N=+5, O=-2.
Simply add the numbers based on the formula:
0= +2 (2(+5) + 2×3(-2))
0= +2 (+ 10 - 12)
0=0
Therefore , The above maths clearly proves that the charges of the elements in the ionic bond is equal to Cu=+2, N=+5, O=-2 Hence, it is the oxidation number.