Question

What is oxidation number of sbf6

Answer 1

) H3AsO3

SnF2

ClF3

PtCl42

[MoO4] 2- : O = - 2; Mo = + 6 (O in general - 2)

Al2O3: O = - 2; Al = - 3

Answer 2

Explanation:

Oxidation number is defined as the number holded by an atom by either gain or loss of electrons when it chemically combines with another atom.

As the oxidation number of a single fluorine atom is -1. So, the oxidation number of six fluorine atoms will be $6 \times (-1)$ = -6.

Let the oxidation number of Sb is x. Therefore, calculate the oxidation number of Sb in $SbF_{6}$ as follows.

                       x + (-6) = 0        (as the given compound is neutral)

                       x = +6

Therefore we can conclude that in the given compound oxidation number of Sb is +6 and F is -1.