What is percentage increased in the area of a rectangle if it's length is is increased by 20%
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Let the length and width of original rectangle be a And b
Area = ab
New length = a + 20% of a
= a + 20a/100
= a + a/5
= 6a/5
New width = b
New Area = 6a/5 × b
= 6ab/5
Increase in area = 6ab/5 - ab
= ab/5
Percentage of Increase = Absolute Increase × 100 / Original area
= ab/5 × 100 / ab
= 100 /5
= 20%
Area = ab
New length = a + 20% of a
= a + 20a/100
= a + a/5
= 6a/5
New width = b
New Area = 6a/5 × b
= 6ab/5
Increase in area = 6ab/5 - ab
= ab/5
Percentage of Increase = Absolute Increase × 100 / Original area
= ab/5 × 100 / ab
= 100 /5
= 20%
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Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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