Question

What is percentage strength of 11.2 v h2o2

Answer 1

Hey there,

◆ Volume strength of H2O2 -
- Volume strength refers to the number of volumes of oxygen gas evolved by one volume of H2O2.

● Answer -
Percentage strength = 34 %

● Explanation -
Let's consider the reaction,
2H2O2 ---> 2H2O + O2

Here,
2×34g H2O2 => 22.4 L O2
68 g H2O2 => 22.4 L O2

Thus, percentage strength of H2O2 is calculated by-
X = 11.2 × 68 / 22.4
X = 34 %

Therefore, percentage strength of given H2O2 is 34% .

Hope this helps you...

Answer 2

"Volume strength is defined as the volume of oxygen at STP liberated from 1 volume of ${ H }_{ 2 }{ O }_{ 2 }$ on heating.

$2{ H }_{ 2 }{ O }_{ 2 }\quad \rightarrow \quad { H }_{ 2 }O+\quad 2{ O }_{ 2 }$According to the stoichiometry, 2 moles f hydrogen peroxide produces one  mole of oxygen and one mole  contains  $22.4\quad M\quad at\quad STP.$

$1\quad mole\quad of\quad { H }_{ 2 }{ O }_{ 2 }\quad gives\quad 11.2\quad L\quad of\quad { O }_{ 2 }$

$M\quad mole\quad of\quad { H }_{ 2 }{ O }_{ 2 }\quad gives\quad 11.2\quad \times \quad M\quad L\quad of\quad { O }_{ 2 }$

$1\quad L\quad of\quad { H }_{ 2 }{ O }_{ 2 }\quad gives\quad 11.2\times \quad M\quad L\quad of\quad { O }_{ 2 }"$