Math, asked by RajivRaman, 1 year ago

what is physical state of water (i)39degree celcius ( ii)200 degree Celsius (IV)0 degree Celsius (v) -39degree celcius​

Answers

Answered by learnerpushp
0

(i) -- liquid

(ii) --- gas

(iii) ---- intermediate position between solid and liquid

(iv) ----- solid

Answered by azizabdurhaman3
0

Answer:

As we know kelvin is the SI unit of temperature,0 degree celsius = 273.16K.For convenience we take 0 degree celsius = 273k.

The boiling point for water is 100degree celsius i.e, 273k + 100 degree celsius = 373 k.

So,for

i)39 degree celsius,

273k+39 degree celsius

=312k.

ii)200 degree celsius,

273k+200 degree celsius

=473k.

iii)0 degree celsius,

273k+0 degree celsius

=273k.

iv) -39 degree celsius,

273k + (-39) degree celsius

=234k.

I hope you got it :)

Step-by-step explanation:

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