what is physical state of water (i)39degree celcius ( ii)200 degree Celsius (IV)0 degree Celsius (v) -39degree celcius
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(i) -- liquid
(ii) --- gas
(iii) ---- intermediate position between solid and liquid
(iv) ----- solid
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Answer:
As we know kelvin is the SI unit of temperature,0 degree celsius = 273.16K.For convenience we take 0 degree celsius = 273k.
The boiling point for water is 100degree celsius i.e, 273k + 100 degree celsius = 373 k.
So,for
i)39 degree celsius,
273k+39 degree celsius
=312k.
ii)200 degree celsius,
273k+200 degree celsius
=473k.
iii)0 degree celsius,
273k+0 degree celsius
=273k.
iv) -39 degree celsius,
273k + (-39) degree celsius
=234k.
I hope you got it :)
Step-by-step explanation:
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