what is probability of getting sum 9 from two throws of a dice
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1/3 is the correct answer for this
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Answer:
1/9 or 1 out of 9 throws
Step-by-step explanation:
take the sample space consisting of all the possible cases
S = {(1,1) ; (1,2) ; (1,3) ; (1,4) ; (1,5) ; (1,6)
(2,1) ; (2,2) ; (2,3) ; (2,4) ; (2,5) ; (2,6)
(3,1) ; (3,2) ; (3,3) ; (3,4) ; (3,5) ; (3,6)
...........................................(6.5) ; (6,6)}
n(S) = 36
∴ there are 9 chances of having a sum of 9 :
A = (3,6) ; (4,5) ; (5,4) ; (6,3)
n(A) = 4
there probability = n(A) / n(s)
= 4/36
=1/9
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