Math, asked by mounika3391, 9 months ago

what is probility getting 52 Sundays in non leap year​

Answers

Answered by singhdevradharmendra
1

Answer:

In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.

Answered by sameer08600
0

Answer:

no of odd days in a normal year

= remainder of 365÷7

=1

therefore no of possible outcomes = sun,mon,Tue,wed,thu,fri,sat=7

therefore probability of getting 52 Sunday = 1/7

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