what is probility getting 52 Sundays in non leap year
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1
Answer:
In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.
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Answer:
no of odd days in a normal year
= remainder of 365÷7
=1
therefore no of possible outcomes = sun,mon,Tue,wed,thu,fri,sat=7
therefore probability of getting 52 Sunday = 1/7
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