Question

what is sin 18/cos72​

Answer 1

Answer:

1

Step-by-step explanation:

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Answer 2

$\huge\bigstar\mathfrak\blue{\underline{\underline{SOLUTION:}}}$

$\frac{sin18 \degree}{cos72 \degree} \\ \\ = > \frac{sin18 \degree}{cos(90 \degree - 18 \degree)} \\ \\ = > \frac{sin18 \degree}{sin18 \degree} \: \: \: (cos(90 - \theta) = sin \theta) \\ \\ = 1$

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