Math, asked by Shikhar1239, 1 year ago

What is smallest no. When divide by 35,56,91 leaves remainder of 7 in each case

Answers

Answered by inhumandrowsey

35 = 7x5

56 = 7x8

91 = 7x13

LCM = 7x5x8x13 = 3640 will be the number perfectly divisible by all three of them and if we add 7 to 3640 we will get 3647 and this is the number when divided by any of the three will always leaves a remainder 7

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