what is stpes of factorazation x2−10x+21
ravikanna:
x2-7x-3x+21=x(x-7)-3(x-7)=(x-7)(x-3)
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x^2-10x+21
By spliting the middle term
x^2-(7+3)x+21
x^2-7x-3x+21
x(x-7)-3(x-7)
(x-7)(x-3)
Answered by
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The correct factorization is as under :
100x2-10+21 = 211
100x2-10+21 = 211
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