Question

What is th H,C,F of 18,42,24

Answer 1

Answer:

$\huge\tt{H.C.F→}$

$\huge\tt{H.C.F→}$

→18= 2x 3x 3

→42=2x 3x 7

→24= 2x 2x2x3

$\large\tt{Common\: factors→}$

$\huge\tt{2\: and \:3}$

$\huge\tt{H.C.F→6}$

Answer 2

Answer:

$18 = 2 \times {3}^{2} \\ 42 = 2 \times 3 \times 7 \\ 24 = {2}^{3} \times 3$

HCF(Common factors and least power)

$= 2 \times 3 \\ = 6$