What is the 25th term of the arithmetic sequence where a1 = 8 and a9 = 48?
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Given (A.P),
a1 = 8
a9 = 48
an = a1 + (n-1)*d
48 = 8 + (9-1)*d
40 = 8*d
d = 5
To find: a25
a25 = a1 + (25-1)*d
a25 = 8 + 24*5 = 8 + 120 = 128
Hence 25th term of A.P is '128'
Hope it helps
a1 = 8
a9 = 48
an = a1 + (n-1)*d
48 = 8 + (9-1)*d
40 = 8*d
d = 5
To find: a25
a25 = a1 + (25-1)*d
a25 = 8 + 24*5 = 8 + 120 = 128
Hence 25th term of A.P is '128'
Hope it helps
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