Question

what is the absissa of a point on the x-axis which is equidistant from (2,-5) and ( -2, 9 ) what is the absisa​

Answer 1

Answer:

absissa 2 and -2

ordinate -5 and 9

Answer 2

Answer:

x = - 6.5

Step-by-step explanation:

d² = ($x_{2}$ - $x_{1}$)² + ($y_{2}$ - $y_{1}$)²

Let E(x,y) is equidistant from point A(- 2, 9) and B(2, - 5) , then

(x + 2)² + (y - 9)² = (x - 2)² + (y + 5)²

x² + 4x + 4 + y² - 18y + 81 = x² - 4x + 4 + y² + 10y + 25

8x - 28y = - 52 ⇔ 2x - 7y = - 13

A point on the x-axis has y = 0

2x - 7 × 0 = - 13 ⇒ x = - 6.5