Question

What is the absolute and gauge pressure of the gas above the liquid surface in the tank . density of oil = 820kg/m^-3, density of mercury = 13.6 * 10^3 kg/m^-3.. length of oil in the tank=1.5m, breadth of oil= 1m and length of mercury in it is = 0.75m

Answer 1

The absolute and guage pressure is 1.14 × 10^5 Pa

Explanation:

gauge pressure,  is defined as the absolute pressure minus the atmospheric pressure

here,

Let P be the pressure of the gas above the liquid surface be P

Absolute pressure = Patm +(hoilρoil + h merc ρ merc) g

(1.5 × 820 + 13.6 × 10^3 × 0.75) g = 1.14 × 10^5 Pa

Pabs = 1.01 × 10^5 Pa + 1.14 × 10^5 Pa

i.e, P abs of gas = 2.15 × 10^5 Pa

Guage pressure is simply abs pressure − atmospheric pressure

= 1.14 × 10^5 Pa

Thus the absolute and guage pressure is 1.14 × 10^5 Pa

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