What is the absolute maximum of the function |x – 3| in the interval [4, 5]?
Answers
Answer:
x-3 45
Step-by-step explanation:
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Given:
A function |x - 3|.
To Find:
The maximum value of the function in the interval [ 4, 5 ].
Solution:
1. The given function is | x- 3 |.
2. The modulus of a number is defined as an absolute value of a number, irrespective of the sign of the number. it is denoted by | |.
Example: modulus of -1, and 1, i.e | -1 | and | 1 | is 1.
3. The mentioned interval is [ 4, 5 ].
- The value of the given function at x = 4 is | 4 - 3 | = +1.
- The value of the given function at x = 4.1 is | 4.1 - 3| = + 1.1
- The value of the given function at x = 4.2 is | 4.2 - 3 | = + 1.2.
4. The value of the given function is increasing as the value of X is increasing in the given interval.
- The function | x - 3 | is a decreasing function in the interval ( -∞ , 3)
- The function | x - 3| is an increasing function in the interval ( 3, ∞ )
- The mentioned interval [ 4, 5] lies in the increasing interval.
5. Therefore, the value of the function increases as the value of x is increasing in the interval [ 4, 5].
6. Therefore, the maximum value of the function is the value at x = 5.
=> value of | x - 3 | at x = 5,
=> | 5 - 3 | = +2.
Therefore, the absolute maximum of the function in the given interval is +2.