Math, asked by nihalkolakkadan, 10 months ago

What is the acceleration of a car if
the speed of the car has increased from 25
km per hour to 40 km per hour in one
minute

Answers

Answered by Anonymous
71

GIVEN

What is the acceleration of a car if

the speed of the car has increased from 25 km per hour to 40 km per hour in one

minute .

SOLUTION

  • Initial velocity (u) = 25 km/h
  • Final velocity (v) = 40km/h
  • Time taken (t) = 1min = 60s
  • Acceleration (a) = ?

→ u = 25km/h

→ u = 25 × 5/18

→ u = 6.9 m/s

Now,

→ v = 40km/h

→ v = 40 × 5/18

→ v = 11.1 m/s

According to the first equation of motion

→ v = u + at

→ 11.1 = 6.9 + a*60

→ 11.1 - 6.9 = 60a

→ 4.2 = 60a

→ a = 4.2/60

→ a = 0.07 m/s²

Hence, acceleration of the car is

0.07m/

Answered by Anonymous
44

Given:

  • Initial velocity = 25 km/hr
  • Final velocity = 40 km/hr
  • Time taken = 1 minute

To Find:

  • Acceleration of the car (a)

Conversions:

1 \: km {hr}^{ - 1}  =  \frac{5}{18}  \: m {s}^{ - 1}

1 \: m {s}^{ - 1}  =  \frac{18}{5}  \: m {s}^{ - 1}

Solution:

Let the initial velocity be u and final velocity as v.

u = 25 km/hr = 25×5/18 = 125/18 m/s

v = 40 km/hr = 40×5/18 = 200/18 m/s

And,

Time taken (t) = 1 min = 60 seconds

Now,

Acceleration(a) =  \dfrac{v - u}{t}  \\  \\  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  =  \frac{ \frac{200 - 125}{18} }{60}  \\  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  \frac{75}{18 \times 60} \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 0.07 \: m {s}^{ - 2} (approx)

Therefore, the acceleration of the car is 0.07 m/s ².

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