# What is the acceleration of a mountain bike if it slows down from 9.4 m/s to 3.0 m/s in a time of 3.75 s?

## Answers

Answered by

7

**Explanation:**

acc. = final velocity - initial velocity/time interval

= 3 - 9.4/3.75

= -6.4/3.75

approximately = - 1.71

Answered by

23

**Answer:**

**Answer:**

- Acceleration of mountain bike will be
**-1.7 m/s²**.

**Explanation:**

**Explanation:**

__Given__

- Initial velocity of bike, u = 9.4 m/s
- Final velocity of bike, v = 3.0 m/s
- Time taken for changing velocity, t = 3.75 s

**To find**

- Acceleration of Bike, a =?

__Formula required__

- First equation of motion

**v = u + a t **

[ where v is final velocity, u is initial velocity, a is acceleration and t is time taken ]

**Calculation**

Using first equation of motion

→ v = u + a t

→ 3.0 = 9.4 + a ( 3.75 )

→ 3.75 a = 3.0 - 9.4

→ 3.75 a = -6.4

→ a = -6.4 / 3.75

→ **a = -1.7 m/s²** [approx.]

Therefore,

**Acceleration of mountain bike will be -1.7 m/s².**

[ negative sign shows that Bike is decelerating ]

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