What is the acceleration of meteor passing by the earth at an altitude of 55000 km
Answers
Answer:
0.11 m/s^2
Explanation:
R = 3600 km = 3.6 × 10^6 m
H = 55000 km = 55 × 10^6 m
R + H = 58.6 × 10^6 m
Therefore using
a = GM/(R + H)^2
= 6.693 × 10^-11 × 6 × 10^24 /( 58.6 × 10^6)^2
= 40.158 × 10^13 / 3433.96 × 10^12
= 0.11 m/s^2
R is radius of earth
H is altitude
G is universal gravitational constant
M is mass of earth
a is acceleration of meteor
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