Question

what is the action of bromine in ethanoic acid on anisole.give equation.

Answer 1

Hey..!!!
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Since NH2 is a ring activating group, therefore it will activate the ring at o and p positions and also bromine solution is in Ethanoic acid which is a protic acid. So  tri-substiution of Br2 takes place.

ALWAYS REMEMBER THAT WHENEVER WE treat any ring activating derivative of benzene with Halogen
Two cases arise:
(i)Solvent used is Non protic acid like CS2-> Then mono-substitution of halogen takes place.
(ii)Solvent used is Protic acid like H2O , ethanoic acid ,etc-> Then tri-substitution of halogen takes place.

Equations- Attachment me se


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Answer 2

anisole undergo bromination with bromine in ethanoic acid,due to activation of benzene ring by the methoxy group para isomer is obtained.