what is the action of bromine in ethanoic acid on anisole.give equation.
Answers
Answered by
9
Hey..!!!
___________
___________
Since NH2 is a ring activating group, therefore it will activate the ring at o and p positions and also bromine solution is in Ethanoic acid which is a protic acid. So tri-substiution of Br2 takes place.
ALWAYS REMEMBER THAT WHENEVER WE treat any ring activating derivative of benzene with Halogen
Two cases arise:
(i)Solvent used is Non protic acid like CS2-> Then mono-substitution of halogen takes place.
(ii)Solvent used is Protic acid like H2O , ethanoic acid ,etc-> Then tri-substitution of halogen takes place.
Equations- Attachment me se
One suggestion: GO THROUGH THIS BOOK MORRISON n BOYD ..you will master organic chemistry
________________
________________
I Hope It's help you.....!!!!
please tick the brainliest answer.
___________
___________
Since NH2 is a ring activating group, therefore it will activate the ring at o and p positions and also bromine solution is in Ethanoic acid which is a protic acid. So tri-substiution of Br2 takes place.
ALWAYS REMEMBER THAT WHENEVER WE treat any ring activating derivative of benzene with Halogen
Two cases arise:
(i)Solvent used is Non protic acid like CS2-> Then mono-substitution of halogen takes place.
(ii)Solvent used is Protic acid like H2O , ethanoic acid ,etc-> Then tri-substitution of halogen takes place.
Equations- Attachment me se
One suggestion: GO THROUGH THIS BOOK MORRISON n BOYD ..you will master organic chemistry
________________
________________
I Hope It's help you.....!!!!
please tick the brainliest answer.
Attachments:
Answered by
9
anisole undergo bromination with bromine in ethanoic acid,due to activation of benzene ring by the methoxy group para isomer is obtained.
Attachments:
Similar questions