Question

What is the active mass of 64 grams of HI in a two litre flask

Answer 1

active mass = mole/ volume
moles if HI = mass/ molar mass
= 64/128
= 0.5
then active mass = 0.5/2
=0.25 mole/liter

Answer 2

active mass= mole/volume
moles in HI=mass/molar mass
=64/128
=0.5
active mass=0.5/2
=0.25