What is the active mass of 64 grams of HI in a two litre flask
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Answered by
18
active mass = mole/ volume
moles if HI = mass/ molar mass
= 64/128
= 0.5
then active mass = 0.5/2
=0.25 mole/liter
moles if HI = mass/ molar mass
= 64/128
= 0.5
then active mass = 0.5/2
=0.25 mole/liter
Answered by
1
active mass= mole/volume
moles in HI=mass/molar mass
=64/128
=0.5
active mass=0.5/2
=0.25
moles in HI=mass/molar mass
=64/128
=0.5
active mass=0.5/2
=0.25
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