Question

what is the acveleration when a card started from rest and acquired a velocity of 8om/s in 10s​

Answer 1

Explanation:

(Refer to Image)

V=at

⇒8=a10

⇒a=0.8m/s

2

V

2

=U

2

+2as

⇒U=8

2

+2×a64

⇒a=

2×64

−64

=−0.5m/s

2

Distance travelled= Area of graph

⇒584=

2

1

×10×8+8×t

1

+

2

1

×16×8

⇒584=40+8t

1

+64

⇒8t

1

=480

⇒t

1

=60

Total time= 10+60+16=86s

solution

Answer 2

Answer:

as car started from rest u=0

v=80m/s

t=8 sec

as we know

v=u+at

80=0+a10

a=80/10

8m/s^2

Explanation:

hope it will help u