Question

What is the age in years of a bone in which the 14c/12c ratio?

Answer 1

The correct answer is
=12 841 years.
=2.75e-13 = (1.3e-12)(1/2)^t/half-life
 =0.21154 = (1/2)^t/half-life ln(2.1154)/ln(1/2) = t/half-life 2.241 = t/half-life t = (2.241)(5730 yrs) t = 12 841 years 

Answer 2

Answer:

The age in years of a bone in which the 14c/12c ratio is 12 841 years.

Explanation:

• Bone age is the degree of maturation of a child's bones. As a person grows from fetal life through childhood, puberty, and finishes growth as a young adult, the bones of the skeleton change in size and shape. These changes can be seen by x-ray techniques. The "bone age" of a child is the average age at which children reach various stages of bone maturation. A child's current height and bone age can be used to predict adult height. For most people, their bone age is the same as their biological age but for some individuals, their bone age is a couple of years older or younger. Those with advanced bone ages typically hit a growth spurt early on but stop growing sooner, while those with delayed bone ages hit their growth spurt later than normal. Children who are below average height do not necessarily have a delayed bone age; in fact, their bone age could be advanced which if left untreated, will stunt their growth.

• At birth, only the metaphyses of the "long bones" are present. The long bones are those that grow primarily by elongation at an epiphysis at one end of the growing bone. The long bones include the femurs, tibias, and fibulas of the lower limb, the humeri, radii, and ulnas of the upper limb (arm + forearm), and the phalanges of the fingers and toes. The long bones of the leg comprise nearly half of the adult height. The other primary skeletal component of height is the spine and skull.

Hence, The age in years of a bone in which the 14c/12c ratio is 12 841 years.

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