Chemistry, asked by saman4138, 1 year ago

What is the amount (in mole) of sodium carbonate (iv) in 5.3g of the compound na2co3=100

Answers

Answered by SrijanShrivastava

4

∵ number of mol = mass ÷ molar mass

n=m/MM

As; gram molar mass of Na₂CO₃ is 106 g

∴ nᴺᵃ²ᶜᴼ³= 53 ÷ 106

∴ n = 0•5 mol

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