Question

What is the amount of H2SO4 (in gram), required to react completely with 100 L of NH3(g) at NTP?​

Answer 1

Answer:218.75g

(Acid)

1H  

2

​

SO  

4

​

 

​

+  

(Base)

2NH  

3

​

 

​

→  

(salt)

(NH  

4

​

)  

2

​

SO  

4

​

 

​

 

∵100litNH  

3

​

  at NTP

No. of moles of NH  

3

​

=  

22.4lit

100lit

​

=(4.46)moles

∵ For 2 moles NH  

3

​

→1moleH  

2

​

SO  

4

​

 

so for 4.46 moles of NH  

3

​

→(  

2

1

​

)×4.46

2.23 moles of H  

2

​

SO  

4

​

 

1 moles H  

2

​

SO  

4

​

=98gm

∴2.23 moles H  

2

​

SO  

4

​

=2.23×98gm

=218.75gm

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