Question

What is the amount of heat released when 0.8 kg of water at
25°C cools until it becomes ice at –6°C? State the assumptions
you make in your calculations.

Answer 1

Answer:

Using the equation for a change in temperature and the value for water from Table 1, we find that Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ is the energy to melt a kilogram of ice. This is a lot of energy as it represents the same amount of energy needed to raise the temperature of 1 kg of liquid water from 0ºC to 79.8ºC.