Question

what is the amount of O2 produced by electrolysis of acidified water using a current of 9.65A for 1 hour​

Answer 1

Answer:

22.4 will be the correct answer ig

Answer 2

Answer:

The number of moles of O2 produced by electrolysis of acidified water using a currect is 0.09 mole

Explanation:

Given : Current(I) -9.65A

Time(t)- 1 hours= 60 min= 3600sec

Faraday (F)= 96500F

Find: Amount of O2 produced by electrolysis

Step by step explanation:

Number of equivalent: It/F

E= 9.65*3600/96500

Number of equivalent= 0.36

Number of moles of O2= equivalent /valence factor

valence factor of O2= 4

Number of moles of O2= 0.36/4=0.09mol •So, the number of moles of O2 produced by electrolysis of acidified water using a currect is 0.09 mole

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