what is the amount of urea in 100ml of solution at 25 degree celcius whose
osmotic pressure is 20.4 atm
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Pressure = 20.4 atm
V = 100ml
T= 25 degree celcius = 298 k
M.M of urea = 60g
Mass of urea = x
C = x/60 * 1000/100 = x/6
Pressure = C*R*T
20.4 = x/6 * 1/12 *298
x = 72*204/10*298 = 14688/2980 = 4.93g
V = 100ml
T= 25 degree celcius = 298 k
M.M of urea = 60g
Mass of urea = x
C = x/60 * 1000/100 = x/6
Pressure = C*R*T
20.4 = x/6 * 1/12 *298
x = 72*204/10*298 = 14688/2980 = 4.93g
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