What is the amount of work done to shift 2colulombs of charge from points A to B having potential differences 10v and 6v?
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Answered by
1
work done = charge ×potential diff
hence W= 2×(10-6)
=8J
Answered by
1
potential difference between A andB is = 10 - 6 = 4v
V = W/Q ( W = work done, Q = charge)
W = VQ
W = 4*2
W = 8 J
The work done is 8J
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